tolong bantu yaa, makasi!
Penjelasan dengan langkah-langkah:
Rumus aljabar dasar :
(a + b)² = a² + 2ab + b²
[tex] {(4 \sqrt{3} + 2 \sqrt{7} )}^{2} \\ = {(4 \sqrt{3} })^{2} + 2(4 \sqrt{3 } \times 2 \sqrt{7} ) + ( {2 \sqrt{7} })^{2} \\ = (16 \times 3) + 2(8 \sqrt{21} ) + (4 \times 7) \\ = 48 + 16 \sqrt{21} + 28 \\ = 76 + 16 \sqrt{42} [/tex]
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